What is (6-6i)-(-2+2i) ?

The solution to (6-6i)-(-2+2i) is 8-8i

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simplify (6-6i)-(-2+2i)

simplify

(6 - 6 i) - (- 2 + 2 i)

8 - 8 i

Solution steps

(6 - 6 i) - (- 2 + 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (6 - (- 2)) + (- 6 - 2) i

Simplify

(6 - (- 2)) + (- 6 - 2) i : 8 - 8 i

= 8 - 8 i

lo g_{10} (300)

(- 3 - x)^{2}

- 1^{\frac{1}{2}}

\frac{( 18 r ^{5} + 36 r ^{4} + 27 r ^{3} )}{9 r}

(a - 6)^{2}