What are the solutions to the equation y^2+2y=35 ?

The solutions to the equation y^2+2y=35 are y=5,y=-7

Find the zeros of y^2+2y=35

The zeros of y^2+2y=35 are y=5,y=-7

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y^{2} + 2 y = 35

y = 5, y = - 7

Solution steps

y^{2} + 2 y = 35

Move

35

to the left side

y^{2} + 2 y - 35 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

y_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 2 + 12}{2 \cdot 1}, y_{2} = \frac{- 2 - 12}{2 \cdot 1}

y = \frac{- 2 + 12}{2 \cdot 1} : 5

y = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 5, y = - 7

\frac{5}{6 x ^{7} y ^{4}} \cdot \frac{5}{3 x ^{6} y ^{3}}

- 3 (w + 5) + 5 w = 2 (w - 6)

3 x^{2} = 8 - 2 x

\frac{3}{5 - 2}

What are the solutions to the equation y^2+2y=35 ?
The solutions to the equation y^2+2y=35 are y=5,y=-7
Find the zeros of y^2+2y=35
The zeros of y^2+2y=35 are y=5,y=-7