What is expand (x+1)(x-2)(x-4) ?

The solution to expand (x+1)(x-2)(x-4) is x^3-5x^2+2x+8

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expand (x+1)(x-2)(x-4)

expand

(x + 1) (x - 2) (x - 4)

x^{3} - 5 x^{2} + 2 x + 8

Solution steps

(x + 1) (x - 2) (x - 4)

Expand

(x + 1) (x - 2) (x - 4) : (x^{2} - x - 2) (x - 4)

= (x^{2} - x - 2) (x - 4)

Distribute parentheses

= x^{2} x + x^{2} (- 4) - xx - x (- 4) - 2 x - 2 (- 4)

Simplify

x^{2} x + x^{2} (- 4) - xx - x (- 4) - 2 x - 2 (- 4) : x^{3} - 5 x^{2} + 2 x + 8

= x^{3} - 5 x^{2} + 2 x + 8

(- 3 sin (t))^{2}

\frac{56 \cdot 15}{35 \cdot 42}

42 \div 7

(- 11 + 9 i) (- 8 + 10 i)

(\frac{x}{2} - \frac{1}{2 x})^{2}

What is expand (x+1)(x-2)(x-4) ?
The solution to expand (x+1)(x-2)(x-4) is x^3-5x^2+2x+8