What is expand (x-1)(x-4)(x-3) ?

The solution to expand (x-1)(x-4)(x-3) is x^3-8x^2+19x-12

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expand (x-1)(x-4)(x-3)

expand

(x - 1) (x - 4) (x - 3)

x^{3} - 8 x^{2} + 19 x - 12

Solution steps

(x - 1) (x - 4) (x - 3)

Expand

(x - 1) (x - 4) (x - 3) : (x^{2} - 5 x + 4) (x - 3)

= (x^{2} - 5 x + 4) (x - 3)

Distribute parentheses

= x^{2} x + x^{2} (- 3) - 5 xx - 5 x (- 3) + 4 x + 4 (- 3)

Simplify

x^{2} x + x^{2} (- 3) - 5 xx - 5 x (- 3) + 4 x + 4 (- 3) : x^{3} - 8 x^{2} + 19 x - 12

= x^{3} - 8 x^{2} + 19 x - 12

\frac{x}{x - 3} + \frac{5 x + 1}{x + 8}

(x^{2} - 2) (x^{2} + 3 x + 5)

(x + 2) (x + 3) (x + 4)

\frac{36}{48}

- 2 - \frac{12}{3}

What is expand (x-1)(x-4)(x-3) ?
The solution to expand (x-1)(x-4)(x-3) is x^3-8x^2+19x-12