What is (\frac{x-9)/(x^3)}{(x^2-81)/(x^2+8x-9)} ?

The solution to (\frac{x-9)/(x^3)}{(x^2-81)/(x^2+8x-9)} is (x-1)/(x^3)

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simplify (\frac{x-9)/(x^3)}{(x^2-81)/(x^2+8x-9)}

simplify

\frac{\frac{x - 9}{x ^{3}}}{\frac{x ^{2} - 81}{x ^{2} + 8 x - 9}}

\frac{x - 1}{x ^{3}}

Solution steps

\frac{\frac{x - 9}{x ^{3}}}{\frac{x ^{2} - 81}{x ^{2} + 8 x - 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x - 9 ) ( x ^{2} + 8 x - 9 )}{x ^{3} ( x ^{2} - 81 )}

Cancel

\frac{( x - 9 ) ( x ^{2} + 8 x - 9 )}{x ^{3} ( x ^{2} - 81 )} : \frac{x - 1}{x ^{3}}

= \frac{x - 1}{x ^{3}}

- 6 + 12

\frac{35}{10}

9 \div \frac{1}{3}

(- 4 - 8 i) - (- 6 + 9 i)

x^{2} y \cdot (- x y) \cdot (- x y^{2})

What is (\frac{x-9)/(x^3)}{(x^2-81)/(x^2+8x-9)} ?
The solution to (\frac{x-9)/(x^3)}{(x^2-81)/(x^2+8x-9)} is (x-1)/(x^3)