What is (5x^2-2x-4)-(6x^5+4x-2x^2-7) ?

The solution to (5x^2-2x-4)-(6x^5+4x-2x^2-7) is -6x^5+7x^2-6x+3

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simplify (5x^2-2x-4)-(6x^5+4x-2x^2-7)

simplify

(5 x^{2} - 2 x - 4) - (6 x^{5} + 4 x - 2 x^{2} - 7)

- 6 x^{5} + 7 x^{2} - 6 x + 3

Solution steps

(5 x^{2} - 2 x - 4) - (6 x^{5} + 4 x - 2 x^{2} - 7)

Apply rule:

(a) = a

(5 x^{2} - 2 x - 4) = 5 x^{2} - 2 x - 4

= 5 x^{2} - 2 x - 4 - (6 x^{5} + 4 x - 2 x^{2} - 7)

Apply the distributive law:

- (a + b) = - a - b

- (6 x^{5} + 4 x - 2 x^{2} - 7) = - 6 x^{5} - 4 x + 2 x^{2} + 7

= 5 x^{2} - 2 x - 4 - 6 x^{5} - 4 x + 2 x^{2} + 7

Group like terms

= - 6 x^{5} + 5 x^{2} + 2 x^{2} - 2 x - 4 x - 4 + 7

Add similar elements:

5 x^{2} + 2 x^{2} = 7 x^{2}

= - 6 x^{5} + 7 x^{2} - 2 x - 4 x - 4 + 7

Add similar elements:

- 2 x - 4 x = - 6 x

= - 6 x^{5} + 7 x^{2} - 6 x - 4 + 7

Add the numbers:

- 4 + 7 = 3

= - 6 x^{5} + 7 x^{2} - 6 x + 3

x^{5} - x^{3}

- (\frac{3}{5})^{2}

(- 1 - 7 i) + (4 + 8 i)

(7 r^{2} - 6 r - 6) (2 r - 4)

4 x^{3}

What is (5x^2-2x-4)-(6x^5+4x-2x^2-7) ?
The solution to (5x^2-2x-4)-(6x^5+4x-2x^2-7) is -6x^5+7x^2-6x+3