What is expand (2x-4)(6x^2-4x+3) ?

The solution to expand (2x-4)(6x^2-4x+3) is 12x^3-32x^2+22x-12

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expand (2x-4)(6x^2-4x+3)

expand

(2 x - 4) (6 x^{2} - 4 x + 3)

12 x^{3} - 32 x^{2} + 22 x - 12

Solution steps

(2 x - 4) (6 x^{2} - 4 x + 3)

Distribute parentheses

= 2 x \cdot 6 x^{2} + 2 x (- 4 x) + 2 x \cdot 3 - 4 \cdot 6 x^{2} - 4 (- 4 x) - 4 \cdot 3

Simplify

2 x \cdot 6 x^{2} + 2 x (- 4 x) + 2 x \cdot 3 - 4 \cdot 6 x^{2} - 4 (- 4 x) - 4 \cdot 3 : 12 x^{3} - 32 x^{2} + 22 x - 12

= 12 x^{3} - 32 x^{2} + 22 x - 12

(x + h)^{4}

(- 3 x + 7) (x^{2} + 6 x + 4)

lo g_{2} (96) - lo g_{2} (3)

lo g_{6} (6^{3})

What is expand (2x-4)(6x^2-4x+3) ?
The solution to expand (2x-4)(6x^2-4x+3) is 12x^3-32x^2+22x-12