What are the solutions to the equation x(4x-9)=-5 ?

The solutions to the equation x(4x-9)=-5 are x= 5/4 ,x=1

Find the zeros of x(4x-9)=-5

The zeros of x(4x-9)=-5 are x= 5/4 ,x=1

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x (4 x - 9) = - 5

x = \frac{5}{4}, x = 1

Solution steps

x (4 x - 9) = - 5

Expand

x (4 x - 9) : 4 x^{2} - 9 x

4 x^{2} - 9 x = - 5

Move

5

to the left side

4 x^{2} - 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 4}

x = \frac{- ( - 9 ) + 1}{2 \cdot 4} : \frac{5}{4}

x = \frac{- ( - 9 ) - 1}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 1

7 a^{2} + 53 a + 28

(- 32 x^{- 10} y^{15})^{\frac{1}{5}}

6 x^{2} + 4 x - 3 = 0

\frac{2 x + 6}{x - 2} < 0

∣ 2 b + 6 ∣ = ∣ b + 1 ∣

What are the solutions to the equation x(4x-9)=-5 ?
The solutions to the equation x(4x-9)=-5 are x= 5/4 ,x=1
Find the zeros of x(4x-9)=-5
The zeros of x(4x-9)=-5 are x= 5/4 ,x=1