What is (2x^2-3x-2)/(6x+3)*(3x+6)/(x^2-4) ?

The solution to (2x^2-3x-2)/(6x+3)*(3x+6)/(x^2-4) is 1

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simplify (2x^2-3x-2)/(6x+3)*(3x+6)/(x^2-4)

simplify

\frac{2 x ^{2} - 3 x - 2}{6 x + 3} \cdot \frac{3 x + 6}{x ^{2} - 4}

1

Solution steps

\frac{2 x ^{2} - 3 x - 2}{6 x + 3} \cdot \frac{3 x + 6}{x ^{2} - 4}

Cancel

\frac{2 x ^{2} - 3 x - 2}{6 x + 3} : \frac{x - 2}{3}

= \frac{x - 2}{3} \cdot \frac{3 x + 6}{x ^{2} - 4}

Cancel

\frac{3 x + 6}{x ^{2} - 4} : \frac{3}{x - 2}

= \frac{x - 2}{3} \cdot \frac{3}{x - 2}

Cross cancel:

\frac{a}{b} \cdot \frac{b}{a} = 1

= 1

17 \times 17

1 + 3.3 lo g_{10} (40)

1 x^{1}

What is (2x^2-3x-2)/(6x+3)*(3x+6)/(x^2-4) ?
The solution to (2x^2-3x-2)/(6x+3)*(3x+6)/(x^2-4) is 1