What is (x^2-3x+4)-(x^3+7x-2) ?

The solution to (x^2-3x+4)-(x^3+7x-2) is -x^3+x^2-10x+6

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simplify (x^2-3x+4)-(x^3+7x-2)

simplify

(x^{2} - 3 x + 4) - (x^{3} + 7 x - 2)

- x^{3} + x^{2} - 10 x + 6

Solution steps

(x^{2} - 3 x + 4) - (x^{3} + 7 x - 2)

Apply rule:

(a) = a

(x^{2} - 3 x + 4) = x^{2} - 3 x + 4

= x^{2} - 3 x + 4 - (x^{3} + 7 x - 2)

Apply the distributive law:

- (a + b) = - a - b

- (x^{3} + 7 x - 2) = - x^{3} - 7 x + 2

= x^{2} - 3 x + 4 - x^{3} - 7 x + 2

Group like terms

= - x^{3} + x^{2} - 3 x - 7 x + 4 + 2

Add similar elements:

- 3 x - 7 x = - 10 x

= - x^{3} + x^{2} - 10 x + 4 + 2

Add the numbers:

4 + 2 = 6

= - x^{3} + x^{2} - 10 x + 6

(10 + 4) - \frac{90}{81}

2. 6^{2}

e^{l n (c o s (x))}

(5 x + 2)^{3}

2.7 (w - 5.2)

What is (x^2-3x+4)-(x^3+7x-2) ?
The solution to (x^2-3x+4)-(x^3+7x-2) is -x^3+x^2-10x+6