What is (\frac{x-4)/(2x^2)}{(3x-12)/(6x)} ?

The solution to (\frac{x-4)/(2x^2)}{(3x-12)/(6x)} is 1/x

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simplify (\frac{x-4)/(2x^2)}{(3x-12)/(6x)}

simplify

\frac{\frac{x - 4}{2 x ^{2}}}{\frac{3 x - 12}{6 x}}

\frac{1}{x}

Solution steps

\frac{\frac{x - 4}{2 x ^{2}}}{\frac{3 x - 12}{6 x}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x - 4 ) \cdot 6 x}{2 x ^{2} ( 3 x - 12 )}

Cancel

\frac{( x - 4 ) \cdot 6 x}{2 x ^{2} ( 3 x - 12 )} : \frac{1}{x}

= \frac{1}{x}

y^{4} (y + 2)^{3} + y^{5} (y + 2)^{4}

\frac{11 - 1}{11}

(x - 9) (x + 6)

(x - 6) (x + 2)

(x + 5) (x^{2} - 5 x + 25)

What is (\frac{x-4)/(2x^2)}{(3x-12)/(6x)} ?
The solution to (\frac{x-4)/(2x^2)}{(3x-12)/(6x)} is 1/x