What is (\frac{x^2+10x+16)/(x^2+6x+8)}{1/(x+4)} ?

The solution to (\frac{x^2+10x+16)/(x^2+6x+8)}{1/(x+4)} is x+8

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simplify (\frac{x^2+10x+16)/(x^2+6x+8)}{1/(x+4)}

simplify

\frac{\frac{x ^{2} + 10 x + 16}{x ^{2} + 6 x + 8}}{\frac{1}{x + 4}}

x + 8

Solution steps

\frac{\frac{x ^{2} + 10 x + 16}{x ^{2} + 6 x + 8}}{\frac{1}{x + 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + 10 x + 16 ) ( x + 4 )}{( x ^{2} + 6 x + 8 ) \cdot 1}

Apply rule:

a \cdot 1 = a

= \frac{( x ^{2} + 10 x + 16 ) ( x + 4 )}{x ^{2} + 6 x + 8}

Cancel

\frac{( x ^{2} + 10 x + 16 ) ( x + 4 )}{x ^{2} + 6 x + 8} : x + 8

= x + 8

3 (x + 3)

x (\frac{1}{x})

\frac{28}{100}

(x + 1) (x - 1) (x + 2)

\frac{14 + 22 i}{2 - 9 i}

What is (\frac{x^2+10x+16)/(x^2+6x+8)}{1/(x+4)} ?
The solution to (\frac{x^2+10x+16)/(x^2+6x+8)}{1/(x+4)} is x+8