What is ((4x^3y-32x^2y^2+16xy^3))/((4xy)) ?

The solution to ((4x^3y-32x^2y^2+16xy^3))/((4xy)) is x^2-8xy+4y^2

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simplify ((4x^3y-32x^2y^2+16xy^3))/((4xy))

simplify

\frac{( 4 x ^{3} y - 32 x ^{2} y ^{2} + 16 x y ^{3} )}{( 4 x y )}

x^{2} - 8 x y + 4 y^{2}

Solution steps

\frac{4 x ^{3} y - 32 x ^{2} y ^{2} + 16 x y ^{3}}{4 x y}

Factor

4 x^{3} y - 32 x^{2} y^{2} + 16 x y^{3} : 4 x y (x^{2} - 8 x y + 4 y^{2})

= \frac{4 x y ( x ^{2} - 8 x y + 4 y ^{2} )}{4 x y}

Cancel the common factor:

4

= \frac{x y ( x ^{2} - 8 x y + 4 y ^{2} )}{x y}

Cancel the common factor:

x

= \frac{y ( x ^{2} - 8 x y + 4 y ^{2} )}{y}

Cancel the common factor:

y

= x^{2} - 8 x y + 4 y^{2}

- 2 - 10

6 \frac{1}{3}

\frac{- 17 + 20 i}{3 - 2 i}

(- 2 x^{3}) \cdot (- 5 x) \cdot (- 3 x^{2})

6 + (- 5)

What is ((4x^3y-32x^2y^2+16xy^3))/((4xy)) ?
The solution to ((4x^3y-32x^2y^2+16xy^3))/((4xy)) is x^2-8xy+4y^2