What is expand (3x-1)(2x^3+4x^2-5) ?

The solution to expand (3x-1)(2x^3+4x^2-5) is 6x^4+10x^3-4x^2-15x+5

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expand (3x-1)(2x^3+4x^2-5)

expand

(3 x - 1) (2 x^{3} + 4 x^{2} - 5)

6 x^{4} + 10 x^{3} - 4 x^{2} - 15 x + 5

Solution steps

(3 x - 1) (2 x^{3} + 4 x^{2} - 5)

Distribute parentheses

= 3 x \cdot 2 x^{3} + 3 x \cdot 4 x^{2} + 3 x (- 5) - 1 \cdot 2 x^{3} - 1 \cdot 4 x^{2} - 1 \cdot (- 5)

Simplify

3 x \cdot 2 x^{3} + 3 x \cdot 4 x^{2} + 3 x (- 5) - 1 \cdot 2 x^{3} - 1 \cdot 4 x^{2} - 1 \cdot (- 5) : 6 x^{4} + 10 x^{3} - 4 x^{2} - 15 x + 5

= 6 x^{4} + 10 x^{3} - 4 x^{2} - 15 x + 5

\frac{35}{5}

x^{2} + 5 x + \frac{25}{4}

- 2 + 0

- y + y

\frac{a ^{3}}{b ^{- 2}} \cdot \frac{a b ^{2}}{a ^{4}}

What is expand (3x-1)(2x^3+4x^2-5) ?
The solution to expand (3x-1)(2x^3+4x^2-5) is 6x^4+10x^3-4x^2-15x+5