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Popular >

|x+4|>= 7

Solution

∣ x + 4 ∣ \geq 7

Solution

x \leq - 11 or x \geq 3

+1

Interval Notation

(- \infty, - 11] \cup [3, \infty)

Solution steps

∣ x + 4 ∣ \geq 7

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 4 \leq - 7 or x + 4 \geq 7

x + 4 \leq - 7 or x + 4 \geq 7

x \leq - 11 or x \geq 3

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5 + c - 3 \leq 6

simplify sqrt(144a^2b^4c^6)simplify

144 a^{2} b^{4} c^{6}

factor 8p^2+7p factor

8 p^{2} + 7 p

Frequently Asked Questions (FAQ)

What is |x+4|>= 7 ?
The solution to |x+4|>= 7 is x<=-11\lor x>= 3