What is expand (2x-3)(3x^2-x-5) ?

The solution to expand (2x-3)(3x^2-x-5) is 6x^3-11x^2-7x+15

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expand (2x-3)(3x^2-x-5)

expand

(2 x - 3) (3 x^{2} - x - 5)

6 x^{3} - 11 x^{2} - 7 x + 15

Solution steps

(2 x - 3) (3 x^{2} - x - 5)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x (- x) + 2 x (- 5) - 3 \cdot 3 x^{2} - 3 (- x) - 3 (- 5)

Simplify

2 x \cdot 3 x^{2} + 2 x (- x) + 2 x (- 5) - 3 \cdot 3 x^{2} - 3 (- x) - 3 (- 5) : 6 x^{3} - 11 x^{2} - 7 x + 15

= 6 x^{3} - 11 x^{2} - 7 x + 15

(2 a - 3 b)^{3}

\frac{- 3}{6}

(3 x^{2} - 1)^{2}

(2 x^{2} + 5) + (x^{3} - 5 x^{2} - 2 x + 3)

\frac{4}{64}

What is expand (2x-3)(3x^2-x-5) ?
The solution to expand (2x-3)(3x^2-x-5) is 6x^3-11x^2-7x+15