What is (10x^2-x+1)-(9x-2) ?

The solution to (10x^2-x+1)-(9x-2) is 10x^2-10x+3

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simplify (10x^2-x+1)-(9x-2)

simplify

(10 x^{2} - x + 1) - (9 x - 2)

10 x^{2} - 10 x + 3

Solution steps

(10 x^{2} - x + 1) - (9 x - 2)

Apply rule:

(a) = a

(10 x^{2} - x + 1) = 10 x^{2} - x + 1

= 10 x^{2} - x + 1 - (9 x - 2)

Apply the distributive law:

- (a - b) = - a + b

- (9 x - 2) = - 9 x + 2

= 10 x^{2} - x + 1 - 9 x + 2

Group like terms

= 10 x^{2} - x - 9 x + 1 + 2

Add similar elements:

- x - 9 x = - 10 x

= 10 x^{2} - 10 x + 1 + 2

Add the numbers:

1 + 2 = 3

= 10 x^{2} - 10 x + 3

\frac{5}{x}

4 + (- 6)

lo g_{\frac{1}{8}} (64)

1 ln (1)

\frac{- 5}{6}