What is expand (x+1)(x-4)(x+3) ?

The solution to expand (x+1)(x-4)(x+3) is x^3-13x-12

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expand (x+1)(x-4)(x+3)

expand

(x + 1) (x - 4) (x + 3)

x^{3} - 13 x - 12

Solution steps

(x + 1) (x - 4) (x + 3)

Expand

(x + 1) (x - 4) (x + 3) : (x^{2} - 3 x - 4) (x + 3)

= (x^{2} - 3 x - 4) (x + 3)

Distribute parentheses

= x^{2} x + x^{2} \cdot 3 - 3 xx - 3 x \cdot 3 - 4 x - 4 \cdot 3

Simplify

x^{2} x + x^{2} \cdot 3 - 3 xx - 3 x \cdot 3 - 4 x - 4 \cdot 3 : x^{3} - 13 x - 12

= x^{3} - 13 x - 12

(m + 7) (m - 4)

\frac{15 a ^{3} b ^{3}}{20 a ^{4} b ^{4}}

\frac{x ^{3} + 8 x ^{2}}{x ^{2} - 64}

- p^{2} (p^{2} - p - 1)

f (x) \cdot g (x)

What is expand (x+1)(x-4)(x+3) ?
The solution to expand (x+1)(x-4)(x+3) is x^3-13x-12