What is expand (x-1)(x-4)(x+3) ?

The solution to expand (x-1)(x-4)(x+3) is x^3-2x^2-11x+12

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expand (x-1)(x-4)(x+3)

expand

(x - 1) (x - 4) (x + 3)

x^{3} - 2 x^{2} - 11 x + 12

Solution steps

(x - 1) (x - 4) (x + 3)

Expand

(x - 1) (x - 4) (x + 3) : (x^{2} - 5 x + 4) (x + 3)

= (x^{2} - 5 x + 4) (x + 3)

Distribute parentheses

= x^{2} x + x^{2} \cdot 3 - 5 xx - 5 x \cdot 3 + 4 x + 4 \cdot 3

Simplify

x^{2} x + x^{2} \cdot 3 - 5 xx - 5 x \cdot 3 + 4 x + 4 \cdot 3 : x^{3} - 2 x^{2} - 11 x + 12

= x^{3} - 2 x^{2} - 11 x + 12

(2 p + q)^{2}

(x - 1) (x - 3) (x - 4)

ln (z)

(a + b)^{2} - (b + c)^{2}

\frac{x ^{2} - 8 x + 12}{x ^{2} - 36}

What is expand (x-1)(x-4)(x+3) ?
The solution to expand (x-1)(x-4)(x+3) is x^3-2x^2-11x+12