What is (9x^2+81x)/(x^3+8x^2-9x) ?

The solution to (9x^2+81x)/(x^3+8x^2-9x) is 9/(x-1)

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simplify (9x^2+81x)/(x^3+8x^2-9x)

simplify

\frac{9 x ^{2} + 81 x}{x ^{3} + 8 x ^{2} - 9 x}

\frac{9}{x - 1}

Solution steps

\frac{9 x ^{2} + 81 x}{x ^{3} + 8 x ^{2} - 9 x}

Factor

9 x^{2} + 81 x : 9 x (x + 9)

= \frac{9 x ( x + 9 )}{x ^{3} + 8 x ^{2} - 9 x}

Factor

x^{3} + 8 x^{2} - 9 x : x (x - 1) (x + 9)

= \frac{9 x ( x + 9 )}{x ( x - 1 ) ( x + 9 )}

Cancel the common factor:

x

= \frac{9 ( x + 9 )}{( x - 1 ) ( x + 9 )}

Cancel the common factor:

x + 9

= \frac{9}{x - 1}

1^{\frac{1}{0}}

\frac{5 x}{x + 2} + \frac{10}{x + 2}

- 4 \times 4

- 1 \cdot (- 4)

100000

What is (9x^2+81x)/(x^3+8x^2-9x) ?
The solution to (9x^2+81x)/(x^3+8x^2-9x) is 9/(x-1)