What is (2x^3-32x)/(2(x^2-4x)) ?

The solution to (2x^3-32x)/(2(x^2-4x)) is x+4

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simplify (2x^3-32x)/(2(x^2-4x))

simplify

\frac{2 x ^{3} - 32 x}{2 ( x ^{2} - 4 x )}

x + 4

Solution steps

\frac{2 x ^{3} - 32 x}{2 ( x ^{2} - 4 x )}

Factor

2 x^{3} - 32 x : 2 x (x^{2} - 16)

= \frac{2 x ( x ^{2} - 16 )}{2 ( x ^{2} - 4 x )}

Factor

x^{2} - 16 : (x + 4) (x - 4)

= \frac{2 x ( x + 4 ) ( x - 4 )}{2 ( x ^{2} - 4 x )}

Cancel the common factor:

2

= \frac{x ( x + 4 ) ( x - 4 )}{x ^{2} - 4 x}

Factor

x^{2} - 4 x : x (x - 4)

= \frac{x ( x + 4 ) ( x - 4 )}{x ( x - 4 )}

Cancel the common factor:

x

= \frac{( x + 4 ) ( x - 4 )}{x - 4}

Cancel the common factor:

x - 4

= x + 4

(x - h)^{3}

(7 + 5 a)^{2}

2 r + 1 + (- 4 r) + 7

\frac{\frac{1}{x}}{\frac{1}{x ^{2}}}

- 4 + (- 6)