What is (11x^4-9x^2+3x+11)-(2x^4+6x^3+2x-9) ?

The solution to (11x^4-9x^2+3x+11)-(2x^4+6x^3+2x-9) is 9x^4-6x^3-9x^2+x+20

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simplify (11x^4-9x^2+3x+11)-(2x^4+6x^3+2x-9)

simplify

(11 x^{4} - 9 x^{2} + 3 x + 11) - (2 x^{4} + 6 x^{3} + 2 x - 9)

9 x^{4} - 6 x^{3} - 9 x^{2} + x + 20

Solution steps

(11 x^{4} - 9 x^{2} + 3 x + 11) - (2 x^{4} + 6 x^{3} + 2 x - 9)

Apply rule:

(a) = a

(11 x^{4} - 9 x^{2} + 3 x + 11) = 11 x^{4} - 9 x^{2} + 3 x + 11

= 11 x^{4} - 9 x^{2} + 3 x + 11 - (2 x^{4} + 6 x^{3} + 2 x - 9)

Apply the distributive law:

- (a + b) = - a - b

- (2 x^{4} + 6 x^{3} + 2 x - 9) = - 2 x^{4} - 6 x^{3} - 2 x + 9

= 11 x^{4} - 9 x^{2} + 3 x + 11 - 2 x^{4} - 6 x^{3} - 2 x + 9

Group like terms

= 11 x^{4} - 2 x^{4} - 6 x^{3} - 9 x^{2} + 3 x - 2 x + 11 + 9

Add similar elements:

11 x^{4} - 2 x^{4} = 9 x^{4}

= 9 x^{4} - 6 x^{3} - 9 x^{2} + 3 x - 2 x + 11 + 9

Add similar elements:

3 x - 2 x = x

= 9 x^{4} - 6 x^{3} - 9 x^{2} + x + 11 + 9

Add the numbers:

11 + 9 = 20

= 9 x^{4} - 6 x^{3} - 9 x^{2} + x + 20

\frac{1}{4} x^{3} + x - 1

1 + 3.322 lo g_{10} (50)

9 lo g_{9} (6)

(6 x - 2)^{2}

\frac{39}{4}

What is (11x^4-9x^2+3x+11)-(2x^4+6x^3+2x-9) ?
The solution to (11x^4-9x^2+3x+11)-(2x^4+6x^3+2x-9) is 9x^4-6x^3-9x^2+x+20