What is (x+5)/(9x+27)*(x^2-9)/(x^2+2x-15) ?

The solution to (x+5)/(9x+27)*(x^2-9)/(x^2+2x-15) is 1/9

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simplify (x+5)/(9x+27)*(x^2-9)/(x^2+2x-15)

simplify

\frac{x + 5}{9 x + 27} \cdot \frac{x ^{2} - 9}{x ^{2} + 2 x - 15}

\frac{1}{9}

Decimal Notation

0.11111 \dots

Solution steps

\frac{x + 5}{9 x + 27} \cdot \frac{x ^{2} - 9}{x ^{2} + 2 x - 15}

Cancel

\frac{x ^{2} - 9}{x ^{2} + 2 x - 15} : \frac{x + 3}{x + 5}

= \frac{x + 5}{9 x + 27} \cdot \frac{x + 3}{x + 5}

Cross-cancel common factor:

x + 5

= \frac{x + 3}{9 x + 27}

Factor

9 x + 27 : 9 (x + 3)

= \frac{x + 3}{9 ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{1}{9}

\frac{22 + 24 i}{- 5 + 9 i}

\frac{7 b}{4} - \frac{3 b}{4}

(- 0.5)^{2}

\frac{x ^{2} - 2 x}{x ^{2} - 5 x + 6} \cdot \frac{x ^{2} + 4 x + 4}{x ^{2} - 4}

(a + 7)^{2}

What is (x+5)/(9x+27)*(x^2-9)/(x^2+2x-15) ?
The solution to (x+5)/(9x+27)*(x^2-9)/(x^2+2x-15) is 1/9