What is expand (x-4)(x-5)(x+2)(x+7) ?

The solution to expand (x-4)(x-5)(x+2)(x+7) is x^4-47x^2+54x+280

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expand (x-4)(x-5)(x+2)(x+7)

expand

(x - 4) (x - 5) (x + 2) (x + 7)

x^{4} - 47 x^{2} + 54 x + 280

Solution steps

(x - 4) (x - 5) (x + 2) (x + 7)

Expand

(x - 4) (x - 5) (x + 2) (x + 7) : (x^{2} - 9 x + 20) (x + 2) (x + 7)

= (x^{2} - 9 x + 20) (x + 2) (x + 7)

Apply FOIL method

(x + 2) (x + 7) : x^{2} + 9 x + 14

= (x^{2} - 9 x + 20) (x^{2} + 9 x + 14)

Distribute parentheses

= x^{2} x^{2} + x^{2} \cdot 9 x + x^{2} \cdot 14 - 9 x x^{2} - 9 x \cdot 9 x - 9 x \cdot 14 + 20 x^{2} + 20 \cdot 9 x + 20 \cdot 14

Simplify

x^{2} x^{2} + x^{2} \cdot 9 x + x^{2} \cdot 14 - 9 x x^{2} - 9 x \cdot 9 x - 9 x \cdot 14 + 20 x^{2} + 20 \cdot 9 x + 20 \cdot 14 : x^{4} - 47 x^{2} + 54 x + 280

= x^{4} - 47 x^{2} + 54 x + 280

(3 x + 4) (2 x - 5)

- 1 - 8

(y - x^{2})^{3}

5 \cdot 13

(- 6 x^{3}) (7 x^{4})

What is expand (x-4)(x-5)(x+2)(x+7) ?
The solution to expand (x-4)(x-5)(x+2)(x+7) is x^4-47x^2+54x+280