What is expand (2x+1)(x^2+8x-3) ?

The solution to expand (2x+1)(x^2+8x-3) is 2x^3+17x^2+2x-3

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expand (2x+1)(x^2+8x-3)

expand

(2 x + 1) (x^{2} + 8 x - 3)

2 x^{3} + 17 x^{2} + 2 x - 3

Solution steps

(2 x + 1) (x^{2} + 8 x - 3)

Distribute parentheses

= 2 x x^{2} + 2 x \cdot 8 x + 2 x (- 3) + 1 \cdot x^{2} + 1 \cdot 8 x + 1 \cdot (- 3)

Simplify

2 x x^{2} + 2 x \cdot 8 x + 2 x (- 3) + 1 \cdot x^{2} + 1 \cdot 8 x + 1 \cdot (- 3) : 2 x^{3} + 17 x^{2} + 2 x - 3

= 2 x^{3} + 17 x^{2} + 2 x - 3

\frac{5 x + 7}{x - 4} - \frac{3 x}{x ^{2} - 9 x + 20}

(2 x - 3) (3 x^{2} + 7 x + 5)

\frac{6}{28}

- 10 + 3

- 2 - 12

What is expand (2x+1)(x^2+8x-3) ?
The solution to expand (2x+1)(x^2+8x-3) is 2x^3+17x^2+2x-3