What are the solutions to the equation w^2+6w-112=0 ?

The solutions to the equation w^2+6w-112=0 are w=8,w=-14

Find the zeros of w^2+6w-112=0

The zeros of w^2+6w-112=0 are w=8,w=-14

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w^{2} + 6 w - 112 = 0

w = 8, w = - 14

Solution steps

w^{2} + 6 w - 112 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 112 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 112) = 22

w_{1, 2} = \frac{- 6 \pm 22}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 6 + 22}{2 \cdot 1}, w_{2} = \frac{- 6 - 22}{2 \cdot 1}

w = \frac{- 6 + 22}{2 \cdot 1} : 8

w = \frac{- 6 - 22}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

w = 8, w = - 14

4 + \frac{2}{3} x = \frac{3}{4}

- 2 x + 5 < 10

11 x^{2} + 33 x = 0

- 188 + 14 x = 111 + x

176

What are the solutions to the equation w^2+6w-112=0 ?
The solutions to the equation w^2+6w-112=0 are w=8,w=-14
Find the zeros of w^2+6w-112=0
The zeros of w^2+6w-112=0 are w=8,w=-14