What is |(2+3i)+(6-2i)| ?

The solution to |(2+3i)+(6-2i)| is square root of 65

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simplify |(2+3i)+(6-2i)|

simplify

∣ (2 + 3 i) + (6 - 2 i) ∣

65

Decimal Notation

8.06225 \dots

Solution steps

∣ (2 + 3 i) + (6 - 2 i) ∣

Simplify

(2 + 3 i) + (6 - 2 i) : 2 + 3 i + 6 - 2 i

= ∣ 2 + 3 i + 6 - 2 i ∣

Simplify

2 + 3 i + 6 - 2 i : 8 + i

= ∣ 8 + i ∣

Apply complex arithmetic rule:

∣ a + bi ∣ = a^{2} + b^{2}

∣ 8 + i ∣ = 8^{2} + 1^{2}

= 8^{2} + 1^{2}

Simplify

8^{2} + 1^{2} : 65

= 65

mn \cdot (- m^{5} n^{3}) \cdot (- m^{3} n^{8})

4 \cdot 1 0^{- 6}

\frac{21}{9}

5 a^{2} - 6 a + 5 a^{2} - 7 a

tan^{2} (x)