What is expand (2x+1)(3x^2-2x-5) ?

The solution to expand (2x+1)(3x^2-2x-5) is 6x^3-x^2-12x-5

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expand (2x+1)(3x^2-2x-5)

expand

(2 x + 1) (3 x^{2} - 2 x - 5)

6 x^{3} - x^{2} - 12 x - 5

Solution steps

(2 x + 1) (3 x^{2} - 2 x - 5)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x (- 2 x) + 2 x (- 5) + 1 \cdot 3 x^{2} + 1 \cdot (- 2 x) + 1 \cdot (- 5)

Simplify

2 x \cdot 3 x^{2} + 2 x (- 2 x) + 2 x (- 5) + 1 \cdot 3 x^{2} + 1 \cdot (- 2 x) + 1 \cdot (- 5) : 6 x^{3} - x^{2} - 12 x - 5

= 6 x^{3} - x^{2} - 12 x - 5

- i (5 - 2 i)^{2}

(x + y)^{9}

\frac{2 x ^{3}}{x ^{2}}

lo g_{π} (1)

2^{7}

What is expand (2x+1)(3x^2-2x-5) ?
The solution to expand (2x+1)(3x^2-2x-5) is 6x^3-x^2-12x-5