What is (7x^2-3x+10)-(-4x^2+6x-4) ?

The solution to (7x^2-3x+10)-(-4x^2+6x-4) is 11x^2-9x+14

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simplify (7x^2-3x+10)-(-4x^2+6x-4)

simplify

(7 x^{2} - 3 x + 10) - (- 4 x^{2} + 6 x - 4)

11 x^{2} - 9 x + 14

Solution steps

(7 x^{2} - 3 x + 10) - (- 4 x^{2} + 6 x - 4)

Apply rule:

(a) = a

(7 x^{2} - 3 x + 10) = 7 x^{2} - 3 x + 10

= 7 x^{2} - 3 x + 10 - (- 4 x^{2} + 6 x - 4)

Apply the distributive law:

- (- a + b) = a - b

- (- 4 x^{2} + 6 x - 4) = 4 x^{2} - 6 x + 4

= 7 x^{2} - 3 x + 10 + 4 x^{2} - 6 x + 4

Group like terms

= 7 x^{2} + 4 x^{2} - 3 x - 6 x + 10 + 4

Add similar elements:

7 x^{2} + 4 x^{2} = 11 x^{2}

= 11 x^{2} - 3 x - 6 x + 10 + 4

Add similar elements:

- 3 x - 6 x = - 9 x

= 11 x^{2} - 9 x + 10 + 4

Add the numbers:

10 + 4 = 14

= 11 x^{2} - 9 x + 14

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What is (7x^2-3x+10)-(-4x^2+6x-4) ?
The solution to (7x^2-3x+10)-(-4x^2+6x-4) is 11x^2-9x+14