What is ((x^3y^2)/(4z))^{-2} ?

The solution to ((x^3y^2)/(4z))^{-2} is (16z^2)/(x^6y^4)

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simplify ((x^3y^2)/(4z))^{-2}

simplify

(\frac{x ^{3} y ^{2}}{4 z})^{- 2}

\frac{16 z ^{2}}{x ^{6} y ^{4}}

Solution steps

(\frac{x ^{3} y ^{2}}{4 z})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{3} y ^{2}}{4 z})^{- 2} = \frac{1}{( \frac{x ^{3} y ^{2}}{4 z} ) ^{2}}

= \frac{1}{( \frac{x ^{3} y ^{2}}{4 z} ) ^{2}}

Simplify

(\frac{x ^{3} y ^{2}}{4 z})^{2} : \frac{x ^{6} y ^{4}}{16 z ^{2}}

= \frac{1}{\frac{x ^{6} y ^{4}}{16 z ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{16 z ^{2}}{x ^{6} y ^{4}}

\frac{4 x ^{3} - 36 x ^{2}}{x ^{2} - 14 x + 45}

(x^{2} - 2 x y + y^{2}) (x - y)

\frac{10}{26}

\frac{6 x}{2}

\frac{19}{7}

What is ((x^3y^2)/(4z))^{-2} ?
The solution to ((x^3y^2)/(4z))^{-2} is (16z^2)/(x^6y^4)