What is (-17-i)/(-9+8i) ?

The solution to (-17-i)/(-9+8i) is 1+i

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simplify (-17-i)/(-9+8i)

simplify

\frac{- 17 - i}{- 9 + 8 i}

1 + i

Solution steps

\frac{- 17 - i}{- 9 + 8 i}

Multiply by the conjugate

\frac{- 9 - 8 i}{- 9 - 8 i}

= \frac{( - 17 - i ) ( - 9 - 8 i )}{( - 9 + 8 i ) ( - 9 - 8 i )}

Simplify

\frac{( - 17 - i ) ( - 9 - 8 i )}{( - 9 + 8 i ) ( - 9 - 8 i )} : \frac{145 + 145 i}{145}

= \frac{145 + 145 i}{145}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{145}{145} + \frac{145}{145} i

Simplify

\frac{145}{145} + \frac{145}{145} i : 1 + i

= 1 + i

\frac{26}{36}

(1 + i 3)^{- 4}

\frac{5}{6} \div \frac{3}{4}

\frac{3}{45}

(x^{2} - 5 x + 4) (x^{2} - 9)