What are the solutions to the equation 5x(x+4)=0 ?

The solutions to the equation 5x(x+4)=0 are x=0,x=-4

Find the zeros of 5x(x+4)=0

The zeros of 5x(x+4)=0 are x=0,x=-4

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5 x (x + 4) = 0

x = 0, x = - 4

Solution steps

5 x (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

(10 + 6 i) (- 2 - 4 i)

\frac{x + 1}{x - 1} \leq 2

12 x^{3} + 8 x^{2} \leq 3 x + 2

\frac{x + 1}{x - 1} > 0

x^{2} - 4 x - 21 > 0

What are the solutions to the equation 5x(x+4)=0 ?
The solutions to the equation 5x(x+4)=0 are x=0,x=-4
Find the zeros of 5x(x+4)=0
The zeros of 5x(x+4)=0 are x=0,x=-4