What is expand (x^{a+1}-3x^{a-2})^2 ?

The solution to expand (x^{a+1}-3x^{a-2})^2 is x^{2(a+1)}-6x^{2a-1}+(3x^{a-2})^2

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expand (x^{a+1}-3x^{a-2})^2

expand

(x^{a + 1} - 3 x^{a - 2})^{2}

x^{2 (a + 1)} - 6 x^{2 a - 1} + (3 x^{a - 2})^{2}

Solution steps

(x^{a + 1} - 3 x^{a - 2})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x^{a + 1} - 3 x^{a - 2})^{2} = (x^{a + 1})^{2} - 2 x^{a + 1} \cdot 3 x^{a - 2} + (3 x^{a - 2})^{2}

= (x^{a + 1})^{2} - 2 x^{a + 1} \cdot 3 x^{a - 2} + (3 x^{a - 2})^{2}

Simplify

(x^{a + 1})^{2} - 2 x^{a + 1} \cdot 3 x^{a - 2} + (3 x^{a - 2})^{2} : x^{2 (a + 1)} - 6 x^{2 a - 1} + (3 x^{a - 2})^{2}

= x^{2 (a + 1)} - 6 x^{2 a - 1} + (3 x^{a - 2})^{2}

(6 x + 3)^{2}

\frac{1}{1 - \frac{3}{4}}

e^{2 l n (x + 1)}

\frac{q ^{m + 3}}{q ^{m - 2}}

(t - 3)^{2}

What is expand (x^{a+1}-3x^{a-2})^2 ?
The solution to expand (x^{a+1}-3x^{a-2})^2 is x^{2(a+1)}-6x^{2a-1}+(3x^{a-2})^2