What is factor 25y^2+20y+4 ?

The solution to factor 25y^2+20y+4 is (5y+2)^2

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factor 25y^2+20y+4

factor

25 y^{2} + 20 y + 4

(5 y + 2)^{2}

Solution steps

25 y^{2} + 20 y + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 y^{2} = (5 y)^{2}

4 = 2^{2}

20 y = 2 \cdot 5 y \cdot 2

= (5 y)^{2} + 2 \cdot 5 y \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(5 y)^{2} + 2 \cdot 5 y \cdot 2 + 2^{2} = (5 y + 2)^{2}

= (5 y + 2)^{2}

x^{3} y + 2 x^{2} y - 3 x y

\frac{1}{a + 1} + \frac{1}{a - 1}

x^{4} - \frac{1}{16}

- 5^{2}

3 (2 c - 5)