What is expand (x+2)(x-2)(2x-1)(x-4) ?

The solution to expand (x+2)(x-2)(2x-1)(x-4) is 2x^4-9x^3-4x^2+36x-16

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expand (x+2)(x-2)(2x-1)(x-4)

expand

(x + 2) (x - 2) (2 x - 1) (x - 4)

2 x^{4} - 9 x^{3} - 4 x^{2} + 36 x - 16

Solution steps

(x + 2) (x - 2) (2 x - 1) (x - 4)

Expand

(x + 2) (x - 2) (2 x - 1) (x - 4) : (x^{2} - 4) (2 x - 1) (x - 4)

= (x^{2} - 4) (2 x - 1) (x - 4)

Apply FOIL method

(x^{2} - 4) (2 x - 1) : 2 x^{3} - x^{2} - 8 x + 4

= (2 x^{3} - x^{2} - 8 x + 4) (x - 4)

Distribute parentheses

= 2 x^{3} x + 2 x^{3} (- 4) - x^{2} x - x^{2} (- 4) - 8 xx - 8 x (- 4) + 4 x + 4 (- 4)

Simplify

2 x^{3} x + 2 x^{3} (- 4) - x^{2} x - x^{2} (- 4) - 8 xx - 8 x (- 4) + 4 x + 4 (- 4) : 2 x^{4} - 9 x^{3} - 4 x^{2} + 36 x - 16

= 2 x^{4} - 9 x^{3} - 4 x^{2} + 36 x - 16

\frac{6}{50}

\frac{sin ( θ )}{1 + cos ( θ )} + \frac{cos ( θ )}{sin ( θ )}

lo g_{125} (9) \cdot lo g_{81} (5)

12 \cdot 12 \cdot 12

t^{3} - 8 t^{2} + t

What is expand (x+2)(x-2)(2x-1)(x-4) ?
The solution to expand (x+2)(x-2)(2x-1)(x-4) is 2x^4-9x^3-4x^2+36x-16