What is factor x^4+x^3-7x^2-x+6 ?

The solution to factor x^4+x^3-7x^2-x+6 is (x-1)(x+1)(x-2)(x+3)

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factor x^4+x^3-7x^2-x+6

factor

x^{4} + x^{3} - 7 x^{2} - x + 6

(x - 1) (x + 1) (x - 2) (x + 3)

Solution steps

x^{4} + x^{3} - 7 x^{2} - x + 6

Use the rational root theorem

= (x - 1) \frac{x ^{4} + x ^{3} - 7 x ^{2} - x + 6}{x - 1}

\frac{x ^{4} + x ^{3} - 7 x ^{2} - x + 6}{x - 1} = x^{3} + 2 x^{2} - 5 x - 6

= (x - 1) (x^{3} + 2 x^{2} - 5 x - 6)

Factor

x^{3} + 2 x^{2} - 5 x - 6 : (x + 1) (x - 2) (x + 3)

= (x - 1) (x + 1) (x - 2) (x + 3)

(2 x) (x)

x (x + 1) (x + 2) (x + 3)

ln (x^{x^{2}})

3 (x - 2) + 2 (4 x - 1)

(- x - 3)^{2}

What is factor x^4+x^3-7x^2-x+6 ?
The solution to factor x^4+x^3-7x^2-x+6 is (x-1)(x+1)(x-2)(x+3)