What is (2x^4+6x^3-8x^2)/(2x^2) ?

The solution to (2x^4+6x^3-8x^2)/(2x^2) is (x-1)(x+4)

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simplify (2x^4+6x^3-8x^2)/(2x^2)

simplify

\frac{2 x ^{4} + 6 x ^{3} - 8 x ^{2}}{2 x ^{2}}

(x - 1) (x + 4)

Solution steps

\frac{2 x ^{4} + 6 x ^{3} - 8 x ^{2}}{2 x ^{2}}

Factor

2 x^{4} + 6 x^{3} - 8 x^{2} : 2 x^{2} (x^{2} + 3 x - 4)

= \frac{2 x ^{2} ( x ^{2} + 3 x - 4 )}{2 x ^{2}}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{2 x ^{2} ( x - 1 ) ( x + 4 )}{2 x ^{2}}

Cancel the common factor:

2

= \frac{x ^{2} ( x - 1 ) ( x + 4 )}{x ^{2}}

Cancel the common factor:

x^{2}

= (x - 1) (x + 4)

\frac{50}{1000}

e^{0} - 1

s (s + 2) (s + 3)

\frac{27}{10}

(x + 8) (x + 7)

What is (2x^4+6x^3-8x^2)/(2x^2) ?
The solution to (2x^4+6x^3-8x^2)/(2x^2) is (x-1)(x+4)