What is factor 8x^3+12x^2+6x+1 ?

The solution to factor 8x^3+12x^2+6x+1 is (2x+1)^3

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factor 8x^3+12x^2+6x+1

factor

8 x^{3} + 12 x^{2} + 6 x + 1

(2 x + 1)^{3}

Solution steps

8 x^{3} + 12 x^{2} + 6 x + 1

Use the rational root theorem

= (2 x + 1) \frac{8 x ^{3} + 12 x ^{2} + 6 x + 1}{2 x + 1}

\frac{8 x ^{3} + 12 x ^{2} + 6 x + 1}{2 x + 1} = 4 x^{2} + 4 x + 1

= (2 x + 1) (4 x^{2} + 4 x + 1)

Factor

4 x^{2} + 4 x + 1 : (2 x + 1) (2 x + 1)

= (2 x + 1) (2 x + 1) (2 x + 1)

Apply exponent rule:

aaa = a^{3}

(2 x + 1) (2 x + 1) (2 x + 1) = (2 x + 1)^{3}

= (2 x + 1)^{3}

(- 2 x + 1)^{2}

\frac{3 x + 1}{x - 1} + \frac{x}{x ^{2} - 1}

\frac{x ^{2} + 3 x - 18}{7 x - 21}

\frac{7 + 23 i}{- 3 - 5 i}

(2 a + 3)^{2}

What is factor 8x^3+12x^2+6x+1 ?
The solution to factor 8x^3+12x^2+6x+1 is (2x+1)^3