What is (2x^3+5x-3)-(2x^3-3x^2+4x) ?

The solution to (2x^3+5x-3)-(2x^3-3x^2+4x) is 3x^2+x-3

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simplify (2x^3+5x-3)-(2x^3-3x^2+4x)

simplify

(2 x^{3} + 5 x - 3) - (2 x^{3} - 3 x^{2} + 4 x)

3 x^{2} + x - 3

Solution steps

(2 x^{3} + 5 x - 3) - (2 x^{3} - 3 x^{2} + 4 x)

Apply rule:

(a) = a

(2 x^{3} + 5 x - 3) = 2 x^{3} + 5 x - 3

= 2 x^{3} + 5 x - 3 - (2 x^{3} - 3 x^{2} + 4 x)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{3} - 3 x^{2} + 4 x) = - 2 x^{3} + 3 x^{2} - 4 x

= 2 x^{3} + 5 x - 3 - 2 x^{3} + 3 x^{2} - 4 x

Group like terms

= 2 x^{3} - 2 x^{3} + 3 x^{2} + 5 x - 4 x - 3

Add similar elements:

2 x^{3} - 2 x^{3} = 0

= 3 x^{2} + 5 x - 4 x - 3

Add similar elements:

5 x - 4 x = x

= 3 x^{2} + x - 3

(x + 6) (x + 8)

(3 x + 1) (x^{2} + 2 x - 10)

\frac{4 mn - 8 m ^{2} n - 2 mn}{2 mn}

(a + 4) (a - 4)

\frac{2 ^{2}}{2 ^{- 3}}

What is (2x^3+5x-3)-(2x^3-3x^2+4x) ?
The solution to (2x^3+5x-3)-(2x^3-3x^2+4x) is 3x^2+x-3