What is log_{4}(64)-log_{3}(3) ?

The solution to log_{4}(64)-log_{3}(3) is 2

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simplify log_{4}(64)-log_{3}(3)

simplify

lo g_{4} (64) - lo g_{3} (3)

2

Solution steps

lo g_{4} (64) - lo g_{3} (3)

lo g_{4} (64) = 3

lo g_{3} (3) = 1

= 3 - 1

Subtract the numbers:

3 - 1 = 2

= 2

lo g_{- 2} (4)

(- 3 + 7 i) - (- 3 - 8 i)

- 1^{π}

- \frac{12}{- 3}

2 x + \frac{1}{x}