What is \sqrt[5]{(x^3*x^{1/2})/(x^{-7)}} ?

The solution to \sqrt[5]{(x^3*x^{1/2})/(x^{-7)}} is x^{21/10}

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simplify \sqrt[5]{(x^3*x^{1/2})/(x^{-7)}}

simplify

x^{\frac{21}{10}}

Solution steps

Cancel

\frac{x ^{3} x ^{\frac{1}{2}}}{x ^{- 7}} : x^{\frac{21}{2}}

Apply radical rule:

assuming

a \geq 0

= x^{\frac{\frac{21}{2}}{5}}

\frac{\frac{21}{2}}{5} = \frac{21}{10}

= x^{\frac{21}{10}}

\frac{x ^{2} - 4 x - 12}{x + 2}

x (x + 2) (x - 3)

\frac{1}{6} \div \frac{1}{2}

\frac{2}{4 x + 12} + \frac{7}{x + 3}

\frac{sin ( x )}{1 + cos ( x )} + cot (x)

What is \sqrt[5]{(x^3*x^{1/2})/(x^{-7)}} ?
The solution to \sqrt[5]{(x^3*x^{1/2})/(x^{-7)}} is x^{21/10}