What is (x^2-4)/(x^2-2x-8) ?

The solution to (x^2-4)/(x^2-2x-8) is (x-2)/(x-4)

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simplify (x^2-4)/(x^2-2x-8)

simplify

\frac{x ^{2} - 4}{x ^{2} - 2 x - 8}

\frac{x - 2}{x - 4}

Solution steps

\frac{x ^{2} - 4}{x ^{2} - 2 x - 8}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x + 2 ) ( x - 2 )}{x ^{2} - 2 x - 8}

Factor

x^{2} - 2 x - 8 : (x + 2) (x - 4)

= \frac{( x + 2 ) ( x - 2 )}{( x + 2 ) ( x - 4 )}

Cancel the common factor:

x + 2

= \frac{x - 2}{x - 4}

\frac{120 x ^{3} y}{25 x y ^{5}}

(x + 8) (x - 4)

(- 11 + i)^{2}

\frac{- 1 + 2 i}{- 9 + 7 i}

(x^{4} + 5 x + 9 + x^{2}) - (x^{3} + 4 x^{2} - 4)