What is (\frac{4x-8)/(x^2-4)}{4/(-2x-4)} ?

The solution to (\frac{4x-8)/(x^2-4)}{4/(-2x-4)} is -2

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simplify (\frac{4x-8)/(x^2-4)}{4/(-2x-4)}

simplify

\frac{\frac{4 x - 8}{x ^{2} - 4}}{\frac{4}{- 2 x - 4}}

- 2

Solution steps

\frac{\frac{4 x - 8}{x ^{2} - 4}}{\frac{4}{- 2 x - 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 4 x - 8 ) ( - 2 x - 4 )}{( x ^{2} - 4 ) \cdot 4}

Cancel

\frac{( 4 x - 8 ) ( - 2 x - 4 )}{( x ^{2} - 4 ) \cdot 4} : - 2

= - 2

\frac{1}{5} \div \frac{1}{2}

(7 + 9 i) + (- 5 i)

(1 + y)^{2}

3 \cdot (- \frac{1}{2})

(2 t - 1)^{2}

What is (\frac{4x-8)/(x^2-4)}{4/(-2x-4)} ?
The solution to (\frac{4x-8)/(x^2-4)}{4/(-2x-4)} is -2