What is expand (x-2)(x+1)(x+5) ?

The solution to expand (x-2)(x+1)(x+5) is x^3+4x^2-7x-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-2)(x+1)(x+5)

expand

(x - 2) (x + 1) (x + 5)

x^{3} + 4 x^{2} - 7 x - 10

Solution steps

(x - 2) (x + 1) (x + 5)

Expand

(x - 2) (x + 1) (x + 5) : (x^{2} - x - 2) (x + 5)

= (x^{2} - x - 2) (x + 5)

Distribute parentheses

= x^{2} x + x^{2} \cdot 5 - xx - x \cdot 5 - 2 x - 2 \cdot 5

Simplify

x^{2} x + x^{2} \cdot 5 - xx - x \cdot 5 - 2 x - 2 \cdot 5 : x^{3} + 4 x^{2} - 7 x - 10

= x^{3} + 4 x^{2} - 7 x - 10

lo g_{3} (\frac{1}{8})

- 4 \times (- 2)

(2 x + 3) (3 - r) - (2 x - 5) (3 - r)

8 \cdot (- 4)

- 4 r - 2 r + 5

What is expand (x-2)(x+1)(x+5) ?
The solution to expand (x-2)(x+1)(x+5) is x^3+4x^2-7x-10