What is (x^2-64)/(x^2-9x)*(x+9)/(x^2+x-72) ?

The solution to (x^2-64)/(x^2-9x)*(x+9)/(x^2+x-72) is (x+8)/(x^2-9x)

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simplify (x^2-64)/(x^2-9x)*(x+9)/(x^2+x-72)

simplify

\frac{x ^{2} - 64}{x ^{2} - 9 x} \cdot \frac{x + 9}{x ^{2} + x - 72}

\frac{x + 8}{x ^{2} - 9 x}

Solution steps

\frac{x ^{2} - 64}{x ^{2} - 9 x} \cdot \frac{x + 9}{x ^{2} + x - 72}

Cancel

\frac{x + 9}{x ^{2} + x - 72} : \frac{1}{x - 8}

= \frac{x ^{2} - 64}{x ^{2} - 9 x} \cdot \frac{1}{x - 8}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x ^{2} - 64 ) \cdot 1}{( x ^{2} - 9 x ) ( x - 8 )}

Apply rule:

a \cdot 1 = a

(x^{2} - 64) \cdot 1 = (x^{2} - 64)

= \frac{x ^{2} - 64}{( x ^{2} - 9 x ) ( x - 8 )}

Factor

x^{2} - 64 : (x + 8) (x - 8)

= \frac{( x + 8 ) ( x - 8 )}{( x ^{2} - 9 x ) ( x - 8 )}

Cancel the common factor:

x - 8

= \frac{x + 8}{x ^{2} - 9 x}

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What is (x^2-64)/(x^2-9x)*(x+9)/(x^2+x-72) ?
The solution to (x^2-64)/(x^2-9x)*(x+9)/(x^2+x-72) is (x+8)/(x^2-9x)