What is (4x^{-2})/(y^{-8)} ?

The solution to (4x^{-2})/(y^{-8)} is (4y^8)/(x^2)

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simplify (4x^{-2})/(y^{-8)}

simplify

\frac{4 x ^{- 2}}{y ^{- 8}}

\frac{4 y ^{8}}{x ^{2}}

Solution steps

\frac{4 x ^{- 2}}{y ^{- 8}}

Simplify

4 x^{- 2} : \frac{4}{x ^{2}}

= \frac{\frac{4}{x ^{2}}}{y ^{- 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{4}{x ^{2} y ^{- 8}}

Simplify

x^{2} y^{- 8} : \frac{x ^{2}}{y ^{8}}

= \frac{4}{\frac{x ^{2}}{y ^{8}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{4 y ^{8}}{x ^{2}}

12 x - 4 (5 x - 1) = 3 - 4 x

- 0.375 c - 11 = 13

4160 + 240

3 (4 y - 5) < - 27

lo g_{7} (2401)