What are the solutions to the equation 8x^2-2x=3 ?

The solutions to the equation 8x^2-2x=3 are x= 3/4 ,x=-1/2

Find the zeros of 8x^2-2x=3

The zeros of 8x^2-2x=3 are x= 3/4 ,x=-1/2

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8 x^{2} - 2 x = 3

x = \frac{3}{4}, x = - \frac{1}{2}

Solution steps

8 x^{2} - 2 x = 3

Move

3

to the left side

8 x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 3) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 8}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 8}

x = \frac{- ( - 2 ) + 10}{2 \cdot 8} : \frac{3}{4}

x = \frac{- ( - 2 ) - 10}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{1}{2}

10 - 2 (- 2)

\frac{3}{4} x - 7 = - 19

- 3 u + 2 = - 10 u + 30

- 6 + 5 x \leq 9

5 ∣ x - 2 ∣ > 15

What are the solutions to the equation 8x^2-2x=3 ?
The solutions to the equation 8x^2-2x=3 are x= 3/4 ,x=-1/2
Find the zeros of 8x^2-2x=3
The zeros of 8x^2-2x=3 are x= 3/4 ,x=-1/2