What is (-8-24i)/(-8+8i) ?

The solution to (-8-24i)/(-8+8i) is -1+2i

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simplify (-8-24i)/(-8+8i)

simplify

\frac{- 8 - 24 i}{- 8 + 8 i}

- 1 + 2 i

Solution steps

\frac{- 8 - 24 i}{- 8 + 8 i}

Multiply by the conjugate

\frac{- 8 - 8 i}{- 8 - 8 i}

= \frac{( - 8 - 24 i ) ( - 8 - 8 i )}{( - 8 + 8 i ) ( - 8 - 8 i )}

Simplify

\frac{( - 8 - 24 i ) ( - 8 - 8 i )}{( - 8 + 8 i ) ( - 8 - 8 i )} : \frac{- 128 + 256 i}{128}

= \frac{- 128 + 256 i}{128}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 128}{128} + \frac{256}{128} i

Simplify

\frac{- 128}{128} + \frac{256}{128} i : - 1 + 2 i

= - 1 + 2 i

\frac{3}{8} \div \frac{1}{2}

49 \frac{1}{2}

(- 7 - 9 i) + (10 + 10 i)

\frac{x ^{2} + 8 x + 15}{x + 5}

(x^{2} - 2 x + 1) (x + 1)