What is (\frac{x^2-81)/(x-9)}{(x^2-17x+72)/(x-8)} ?

The solution to (\frac{x^2-81)/(x-9)}{(x^2-17x+72)/(x-8)} is (x+9)/(x-9)

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simplify (\frac{x^2-81)/(x-9)}{(x^2-17x+72)/(x-8)}

simplify

\frac{\frac{x ^{2} - 81}{x - 9}}{\frac{x ^{2} - 17 x + 72}{x - 8}}

\frac{x + 9}{x - 9}

Solution steps

\frac{\frac{x ^{2} - 81}{x - 9}}{\frac{x ^{2} - 17 x + 72}{x - 8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 81 ) ( x - 8 )}{( x - 9 ) ( x ^{2} - 17 x + 72 )}

Cancel

\frac{( x ^{2} - 81 ) ( x - 8 )}{( x - 9 ) ( x ^{2} - 17 x + 72 )} : \frac{x + 9}{x - 9}

= \frac{x + 9}{x - 9}

1 + 3.322 lo g_{10} (30)

i \times i

36 \frac{1}{2}

49 x^{2} - \frac{16}{25}

\frac{12}{27}

What is (\frac{x^2-81)/(x-9)}{(x^2-17x+72)/(x-8)} ?
The solution to (\frac{x^2-81)/(x-9)}{(x^2-17x+72)/(x-8)} is (x+9)/(x-9)