What is 2x^{-1}\times 4x^2 ?

The solution to 2x^{-1}\times 4x^2 is 8x

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simplify 2x^{-1}\times 4x^2

simplify

2 x^{- 1} \cdot 4 x^{2}

8 x

Solution steps

2 x^{- 1} \cdot 4 x^{2}

Multiply the numbers:

2 \cdot 4 = 8

= 8 x^{- 1} x^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{- 1} x^{2} = x^{- 1 + 2}

= 8 x^{- 1 + 2}

Add/Subtract the numbers:

- 1 + 2 = 1

= 8 x^{1}

Apply exponent rule:

a^{1} = a

x^{1} = x

= 8 x

\frac{5}{2}

\frac{16 + 20 i}{9 + i}

6 a^{2} b + 7 a^{2} b

(- 2 x^{3})^{3}

(2 t^{2})^{2}